What is the RF frequency corresponding to a wavelength of 8.33 meters in air?

Prepare for the Associate Certified Electronics Technician (CET) Exam. Study with challenging multiple choice questions, hints, and explanations. Ensure you're ready for exam day!

To determine the RF frequency corresponding to a wavelength of 8.33 meters in air, you can use the fundamental relationship between wavelength (λ), frequency (f), and the speed of light (c). The equation is given by:

[ f = \frac{c}{\lambda} ]

In this context, the speed of light in air is approximately 3 x 10^8 meters per second. Substituting the values:

[ f = \frac{3 \times 10^8 \text{ m/s}}{8.33 \text{ m}} ]

Calculating this gives:

[ f \approx 3.6 \times 10^7 \text{ Hz} ]

Or, converting this result into megahertz:

[ f \approx 36 \text{ MHz} ]

This shows that the frequency corresponding to a wavelength of 8.33 meters in air is indeed approximately 36 MHz. Understanding this relationship is crucial in RF engineering and helps in applications involving antennas, broadcasting, and communications technology.

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