Associate Certified Electronics Technician (CET) Practice Exam

To determine the decibel loss when a signal power changes, we can use the formula for power in decibels, which is given by:

\[ dB = 10 \times \log_{10}\left(\frac{P_{received}}{P_{transmitted}}\right) \]

In this scenario, the transmitted power is 10W and the received power is 5W. Plugging these values into the formula gives:

\[ dB = 10 \times \log_{10}\left(\frac{5W}{10W}\right) \]

\[ dB = 10 \times \log_{10}(0.5) \]

Now, the logarithm of 0.5 can be calculated. Knowing that \(\log_{10}(0.5) \approx -0.301\):

\[ dB = 10 \times (-0.301) \]

\[ dB = -3.01 \]

Rounding this to the nearest whole number gives a loss of approximately -3 dB. Since we are looking for the absolute value of the loss, it translates to a loss of 3 dB.

Thus, the statement pertaining to a 3 dB loss is accurate,