What is the effective voltage of a 100V peak to peak sine wave?

To determine the effective voltage of a 100V peak-to-peak sine wave, it is important to understand the relationship between peak-to-peak voltage and root mean square (RMS) voltage. The effective voltage, or RMS voltage, for a sine wave can be calculated using the peak voltage, which is half of the peak-to-peak voltage.

Since the peak-to-peak voltage is given as 100V, the peak voltage is calculated as follows:

Peak Voltage = Peak-to-Peak Voltage / 2 = 100V / 2 = 50V

To find the RMS voltage of a sine wave, the peak voltage must then be multiplied by a specific factor, which is approximately 0.707 (or 1/√2).

RMS Voltage = Peak Voltage × 0.707 ≈ 50V × 0.707 ≈ 35.35V

Thus, the effective voltage of a 100V peak-to-peak sine wave is approximately 35.35V. This method of using the peak voltage to find the RMS value is standard practice in electrical engineering when dealing with alternating currents expressed in sine waveforms.