Given a power supply that measures 50 volts no load and 40 volts full load, what is the percent regulation?

Given a power supply that measures 50 volts no load and 40 volts full load, what is the percent regulation?

• A. 20%
• B. 10%
• C. 25%
• D. 15%

Answer: (A)

To calculate percent regulation for a power supply, you can use the formula: \[ \text{Percent Regulation} = \frac{\text{No Load Voltage} - \text{Full Load Voltage}}{\text{No Load Voltage}} \times 100 \] In this scenario, the no load voltage is 50 volts, and the full load voltage is 40 volts. Plugging these values into the formula gives: \[ \text{Percent Regulation} = \frac{50V - 40V}{50V} \times 100 = \frac{10V}{50V} \times 100 = 20\% \] This indicates that the power supply experiences a voltage drop of 10 volts from no load to full load, which represents 20% of the no load voltage. Percent regulation is a critical metric for evaluating the stability and performance of a power supply, showing how much the output voltage drops under load conditions compared to its no load state. Thus, the correct answer is 20%, which accurately reflects the ratio of the voltage change to the no load voltage, indicating the efficiency of the power supply during operation.

To calculate percent regulation for a power supply, you can use the formula:

[

\text{Percent Regulation} = \frac{\text{No Load Voltage} - \text{Full Load Voltage}}{\text{No Load Voltage}} \times 100

]

In this scenario, the no load voltage is 50 volts, and the full load voltage is 40 volts. Plugging these values into the formula gives:

[

\text{Percent Regulation} = \frac{50V - 40V}{50V} \times 100 = \frac{10V}{50V} \times 100 = 20%

]

This indicates that the power supply experiences a voltage drop of 10 volts from no load to full load, which represents 20% of the no load voltage. Percent regulation is a critical metric for evaluating the stability and performance of a power supply, showing how much the output voltage drops under load conditions compared to its no load state.

Thus, the correct answer is 20%, which accurately reflects the ratio of the voltage change to the no load voltage, indicating the efficiency of the power supply during operation.