As the plates of a variable capacitor open, what happens to the capacitance?

Prepare for the Associate Certified Electronics Technician (CET) Exam. Study with challenging multiple choice questions, hints, and explanations. Ensure you're ready for exam day!

When the plates of a variable capacitor open, the effective surface area of the plates decreases. Capacitance is defined by the formula:

[ C = \frac{\varepsilon \cdot A}{d} ]

where ( C ) is capacitance, ( \varepsilon ) is the permittivity of the dielectric material between the plates, ( A ) is the area of the plates, and ( d ) is the distance between them.

As the plates are separated (opened), the area ( A ) effectively reduces, which leads to a decrease in capacitance. Additionally, since the distance ( d ) increases, this further contributes to a decrease in capacitance since capacitance is inversely proportional to the distance between the plates. Consequently, as the plates continue to open, the capacitance will continue to decrease.

Understanding how capacitance behaves in relation to plate area and separation distance clarifies why the capacitance decreases in this scenario. This principle is fundamental in electronic circuit design, especially in tuning circuits and filters where variable capacitors are used.

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